What are the limits of f(x) for different values of p and q?

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The discussion focuses on determining the limit of the function f(x) defined as f(x) = lim (n→∞) P(n)/Q(n), where P(x) and Q(x) are polynomial functions of degrees p and q, respectively. The key conclusions are that when p < q, f(x) equals 0; when p > q, f(x) equals ∞; and when p = q, f(x) equals the ratio of the leading coefficients a0/b0. The participants emphasize the importance of understanding polynomial behavior at infinity and the application of limit definitions.

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Homework Statement


P(x)=a0*x^(p)+a1*x^(p-1)+a2*x^(p-2)...
Q(x)=b0*x^(q)+b1*x^(q-1)+b2*x^(q-2)...

f(x)=lim (n[tex]\rightarrow[/tex][tex]\infty[/tex])P(n)/Q(n)

prove what f(x) is equal to for when p<q,q<p,p=q

Find the different values of f(x)

Homework Equations



The only information that I know I can use is the definition of a limit, the squeeze principle,, 1/n converges as n goes to infinity, the limit of a^n where a is a fixed number, and that you can multiply, add, and divide limits.

The Attempt at a Solution



Let
P(n)/Q(n)=(a0*n^(p)+a1*n^(p-1)+a2*n^(p-2)...)/(b0*n^(q)+b1*n^(q-1)+b2*n^(q-2)...)
I'll just start off by asking my first question. It is not legal to divide the top by n^p and the bottom by n^q correct? I would assume its not ok to do because the ratio between the two is not 1.
 
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If my wording isn't clear please let me know and I can reword what I said.
 

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