- #1
um0123
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Homework Statement
In the problem to find the value of: http://img8.imageshack.us/img8/6827/powpic1.jpg
You can solve it in this way:
[tex]x=\frac{1}{1+x}[/tex]
where the x in 1 + x is http://img24.imageshack.us/img24/3751/powpic2.jpg
which makes the equation:
[tex]x=\frac{1}{1+x}[/tex]
[tex]x^2 + x = 1[/tex]
[tex]x^2 + x - 1 = 0[/tex]
Homework Equations
then i used quadratic equation
[tex]x=-\frac{1}{2} \pm \frac{\sqrt{5}}{2}[/tex]
Use the method above to solve these equations:
1)http://img20.imageshack.us/img20/5903/powpic3.jpg
2)http://img196.imageshack.us/img196/8639/powpic4.jpg
3)http://img5.imageshack.us/img5/7536/powpic5.jpg
4)MAKE UP YOUR OWN!
The Attempt at a Solution
i used quadratic equation on the problem in the setup to get:
[tex]x=-\frac{1}{2} \pm \frac{\sqrt{5}}{2}[/tex]
plug that into the original equation to get
x = 0.365489 or -0.576014
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I followed this method for the first problem and got:
x=1.61803 or x=0.61803
which is kind of odd, I am wondering if I am doing it correctly.
Im going to proceed with the rest, but i am worried i am doing this all wrong.
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