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Instantaneous Center of Zero Velocity

  1. Oct 1, 2012 #1
    1. The problem statement, all variables and given/known data
    281fN.png

    Why is the angular velocity of link BD the same as the angular velocity of ICD?

    Shouldn't it be ωICD=vD/rD/IC?
     
  2. jcsd
  3. Oct 2, 2012 #2
    BD is a rigid body. All of its points have the same angular velocity. The angular velocity of point D is easiest to compute. If ICD were a rigid body firmly attached to BD, then it would also have the same angular velocity.
     
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