Instantaneous Center of Zero Velocity

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
theBEAST
Messages
361
Reaction score
0

Homework Statement


281fN.png


Why is the angular velocity of link BD the same as the angular velocity of ICD?

Shouldn't it be ωICD=vD/rD/IC?
 
Physics news on Phys.org
BD is a rigid body. All of its points have the same angular velocity. The angular velocity of point D is easiest to compute. If ICD were a rigid body firmly attached to BD, then it would also have the same angular velocity.