Integ 1 / sqr root(a^2 - x^2 )

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Homework Help Overview

The discussion revolves around the integration of the function 1 / √(a² - x²), which falls under the subject area of calculus, specifically integral calculus. Participants are seeking assistance in understanding the integration process and related concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential use of inverse trigonometric functions, particularly arcsin, in solving the integral. There is some confusion regarding the correct form of the numerator when applying this method.

Discussion Status

Some guidance has been offered regarding the integration approach, with references to inverse trigonometric identities. However, there remains a lack of consensus on the details of the integration process, as participants are clarifying their understanding of the components involved.

Contextual Notes

Participants are navigating through the specifics of the integration technique and its application, with some uncertainty about the algebraic manipulation required for the integral.

teng125
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does anybody knows how to do integ 1 / sqr root(a^2 - x^2 )...
pls help...
 
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Think inverse trig.
 
ya i thought of using diff of arcsin ax = a / sqr root (1 - (ax)^2 )
but if i do so the numerator will be 1/a^2 rite??

pls help
 
Close, it would be 1/a, like this: [tex]\int\frac{du}{\sqrt{a^2-u^2}} = arcsin \frac{u}{a} + C[/tex]
 

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