MHB Integrating Factors for Solving Linear Differential Equations

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The discussion focuses on solving a linear differential equation by transforming it into the standard form dy/dx + p(x)y = q(x). The user initially divided by (1-x^2) to simplify the equation but struggled to find Q(x). A participant provided a manipulation of the right-hand side, leading to the new form of the ODE. The next step involves calculating the integrating factor, expressed as an exponential integral. The conversation emphasizes the importance of correctly applying integration techniques to solve the differential equation.
mahmoud shaaban
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Can i have help with this linear differential equation ?
First, i divided by (1-x^2) to be like dy/dx + p(x)y= q(x). But i could not obtain Q(x).
Any help will be welcomed.
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Let's look at what happens when we divide the RHS by $1-x^2$:

$$\frac{(1-x)\sqrt{1-x^2}}{1-x^2}=\frac{1-x}{\sqrt{1-x^2}}=\frac{1-x}{\sqrt{(1+x)(1-x)}}=\sqrt{\frac{1-x}{1+x}}$$

So, the ODE is now:

$$\d{y}{x}+\frac{x^2}{1-x^2}y=\sqrt{\frac{1-x}{1+x}}$$

Next, we want to compute the integrating factor:

$$\mu(x)=\exp\left(\int\frac{x^2}{1-x^2}\,dx\right)$$

Can you proceed?
 

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