Integrating over a delta function

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SUMMARY

The discussion focuses on the integration of a delta function, specifically \(\delta(m)\), where \(m\) is defined as a constant multiplied by the difference between two variables, \(s\) and \(s'\). The user expresses confusion about integrating over \(s\) or \(s'\) due to the dependency of the delta function on \(s\). The key takeaway is the application of the property \(\int ds \delta(s-s') f(s) = f(s')\), emphasizing the need to eliminate the constant before performing the integration.

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raisin_raisin
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Hello,
I have just integrated over one variable, x and have now got a delta function
[tex]\delta(m)[/tex]

where m = constant * (s-s')

now I have to integrate over either s or s' but I am a bit confused
since if I integrate over say s then the delta function depends on s.

Hope I have explained clearly enough, thanks for reading.
 
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[tex]\int ds \delta(s-s') f(s) = f(s').[/tex]


Notice too that there is no constant there, so you have to get rid of it first.
 
clamtrox said:
[tex]\int ds \delta(s-s') f(s) = f(s').[/tex]


Notice too that there is no constant there, so you have to get rid of it first.

Thank you very much.
 

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