Interpreting Weird Results: J_u, P_1 and T_1

AI Thread Summary
The discussion revolves around interpreting results for thermal radiation between three sheets, focusing on energy balance equations. The user is confused about the implications of their calculations, particularly regarding the relationship between temperatures T1 and T2 and the power P23. They initially derived equations based on energy emitted and absorbed by the sheets but struggled with the concept of equilibrium and the role of emissivity and absorptivity. Clarifications were made that emissions and absorptions cannot be assumed to be in balance, and the need for a net energy flow was emphasized. Ultimately, the user recognized that P23 should not depend on T1, leading to a more coherent understanding of the energy interactions between the sheets.
baseballfan_ny
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Homework Statement
A sheet (“sheet 1”) of area A having emissivity ##e_1## is held at temperature ##T_1## so that it emits a total power ##P_1## to the right (i.e., energy per unit time). Let σB be the Stefan-Boltzmann constant and neglect all edge effects.

a. In terms of ##P_1##, calculate temperature ##T_1## of sheet 1.

Two additional black sheets, each of area A and having emissivities ##e_2## = 1 and ##e_3## = 1, are now added to the right of sheet 1. (See figure below) The spacings between the pairs of sheets is d, such that ##d^2## is much less than A . The temperature ##T_2## of the middle sheet (2) is allowed to vary and the right-hand sheet (3) is held at a fixed temperature ##T_3## = 0.

b. Assume that sheet 2 reaches a steady state temperature ##T_2##. What is the power flow ##P_{23}## (total power, not power per unit area) emitted by sheet 2 to the right-hand sheet, i.e., from sheet 2 to sheet 3? Your answer should be given in terms of in terms of ##T_2##, A, d, ##\sigma_B##, and ##e_1## only. [Note: Not all of these parameters should appear in your answer.]

c. Determine ##T_2## in terms of ##T_1##, A, d, ##\sigma_B## and ##e_1## only.
Relevant Equations
Stefan-Boltzmann
## J_u = e \sigma_B T^4 ##
I need someone to check my work, because I'm getting weird results that I'm not able to interpret physically for parts b and c. Thanks in advance.

For part a...

##J_u = e_1 \sigma_B T^4##
##P_1 = AJ_u = e_1 \sigma_B AT_1^4##
## T_1 = \left( \frac {P_1} {e_1 \sigma_B A} \right)^{\frac 1 4} ##

For part b...
pf_hw6_1.jpg

I'm using the idea that energy emitted by sheet 2 = energy absorbed by sheet 2

## \sigma_B T_2^4 + \frac {P_{23}} {A} = e_1 \sigma_B T_1^4 + (1 - e_1) \sigma_B T_2^4 ##
## \frac {P_{23}} {A} = e_1 \sigma_B \left( T_1^4 - T_2^4 \right) ##
## P_{23} = A e_1 \sigma_B \left( T_1^4 - T_2^4 \right) ##

For part c...
pf_hw6_2.jpg

I'm using the idea that energy emitted by sheet 1 = energy absorbed by sheet 1

## e_1 \sigma_B T_1^4 + \left( 1 - e_1 \right) \sigma_B T_2^4 = \sigma_B T_2^4 ##
## e_1 \sigma_B T_1^4 = e_1 \sigma_B T_2^4 ##
## T_1 = T_2##

Now this has been bothering me, because if ##T_1 = T_2##, then ##P_{23} = 0##? I can't seem to make sense of that.
 
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baseballfan_ny said:
For part b...
View attachment 291135
I'm using the idea that energy emitted by sheet 2 = energy absorbed by sheet 2

## \sigma_B T_2^4 + \frac {P_{23}} {A} = e_1 \sigma_B T_1^4 + (1 - e_1) \sigma_B T_2^4 ##
I don't see how you get this equation. Surely emissions from the third sheet are part of the middle sheet's energy balance. And can't you immediately write down how ##P_{23}## depends on ##T_2## without reference to the other sheets?
 
haruspex said:
Surely emissions from the third sheet are part of the middle sheet's energy balance.
But ##T_3## = 0, so it doesn't emit any energy, right? I suppose it can absorb energy emitted by ##P_{23}##.

haruspex said:
And can't you immediately write down how P23 depends on T2 without reference to the other sheets?
I had thought that originally ... that ##P_{23} = A\sigma_B T_2^4##, but I think there has to be equilibrium maintained? So that's why applied those conditions.

I just don't think it makes sense for ##P_{23} = 0##.
 
baseballfan_ny said:
But T3 = 0
Sorry, I missed that.
baseballfan_ny said:
I had thought that originally ... that ##P_{23} = A\sigma_B T_2^4##, but I think there has to be equilibrium maintained?
That equation is a valid answer whether or not equilibrium is maintained. The answer you gave includes T1, which is not allowed.

baseballfan_ny said:
I'm using the idea that energy emitted by sheet 1 = energy absorbed by sheet 1

## e_1 \sigma_B T_1^4 + \left( 1 - e_1 \right) \sigma_B T_2^4 = \sigma_B T_2^4 ##
Please explain how you get that equation.
One thing I am not clear on is whether you are supposed to assume all arriving energy is absorbed, or whether in each case absorptivity equals emissivity, so (1-e) would be reflected (much complicating matters).
 
haruspex said:
Please explain how you get that equation.
My idea was that the total amount of energy emitted by sheet 1 = total amount of energy "delivered" to sheet 1 (I realized I wrote "absorbed" instead of "delivered" in Post 1 so that was probably confusing). The first term is the energy emitted by sheet 1, since it has absorptivity = emissivity = ##e_1##. The 2nd term was the amount of energy (originating from sheet 2) reflected by sheet 1. The right hand side is the amount of energy delivered to sheet 1 from sheet 2.
haruspex said:
One thing I am not clear on is whether you are supposed to assume all arriving energy is absorbed, or whether in each case absorptivity equals emissivity, so (1-e) would be reflected (much complicating matters).
I believe I'm supposed to take ##a = e## by Kirchoff's Law.

haruspex said:
That equation is a valid answer whether or not equilibrium is maintained. The answer you gave includes T1, which is not allowed.
Ok so I'm getting something new. I think I'm supposed to say sheet 2 emits ##J = \sigma_B T_2^4## and then enforce equilibrium.

So then my answer to part b would just be...
## P_{23} = A \sigma_B T_2^4 ##.

Then for part c I would enforce equilibrium on sheet 2... that however much is absorbed by it is emitted...

##(1 - e_1)\sigma_B T_2^4 + e_1 \sigma_B T_1^4 = \sigma_B T_2^4 ##

where the first term is the amount reflected by sheet 1 and reabsorbed by sheet 2, the second term is the amount emitted by sheet 1 and absorbed by sheet 2, and the right hand side term is the amount emitted by sheet 2.

So...

## \sigma_B T_2^4 - e_1\sigma_B T_2^4 + e_1\sigma_B T_1^4 = \sigma_B T_2^4 ##

##- e_1\sigma_B T_2^4 + e_1\sigma_B T_1^4 = 0 ##

##T_1 = T_2##, but as you pointed out, ##P_{23} = A \sigma_B T_2^4## and should not be in terms of ##T_1## so I no longer have ##P_{23} = 0##
 
baseballfan_ny said:
My idea was that the total amount of energy emitted by sheet 1 = total amount of energy "delivered" to sheet 1
You cannot assume the emissions and absorptions of sheet 1 are in balance. There will surely be a net flow of energy from 1 to 3, even though 2 is at a constant temperature.
baseballfan_ny said:
The 2nd term was the amount of energy (originating from sheet 2) reflected by sheet 1
If you have to allow for reflections then there are in principle infinitely many.
Create unknowns for the total flow from 1 to 2 and 2 to 1 and write equations relating these to the emissions and absorptions.
 
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