MHB Introduction to RAD (Rapid Application Development)

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    Bicycle Speed
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The discussion revolves around calculating the speed of a bicycle with tires that have a radius of 13 inches, turning at a rate of 200 revolutions per minute. The calculation yields a speed of approximately 15.5 miles per hour, confirming the method used. Participants clarify that "rev" is dimensionless, which aids in the calculation process. One user expresses a desire to start a new thread to seek further clarification on Rapid Application Development (RAD). The conversation effectively combines mathematical reasoning with practical application.
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The tires of a bicycle have radius of $13 \text{ in}$ and are turning at a rate of
$\displaystyle\frac{200\text{ rev}}{\text{min}}$

How fast is the bicycle traveling in
$\displaystyle\frac{\text{mi}}{\text{hr}}$

well my try on this is.

$
\displaystyle 26\pi\text{ in }
\cdot
\frac{200\text{ rev}}{\text {min}}
\cdot
\frac{\text {ft}}{12\text{ in}}
\cdot
\frac{\text {mi}}{5280\text{ ft}}
\cdot
\frac{60\text { min}}{\text{ hr}}
\approx\frac{15.5\text { mi}}{\text{ hr}}
$
no answer given so hope this is it..:cool:
assume "rev" not a unit measure but doesn't cancel out so its not carried thru..
 
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Re: speed of a Bicycle

karush said:
The tires of a bicycle have radius of $13 \text{ in}$ and are turning at a rate of
$\displaystyle\frac{200\text{ rev}}{\text{min}}$

How fast is the bicycle traveling in
$\displaystyle\frac{\text{mi}}{\text{hr}}$

well my try on this is.

$
\displaystyle 26\pi\text{ in }
\cdot
\frac{200\text{ rev}}{\text {min}}
\cdot
\frac{\text {ft}}{12\text{ in}}
\cdot
\frac{\text {mi}}{5280\text{ ft}}
\cdot
\frac{60\text { min}}{\text{ hr}}
\approx\frac{15.5\text { mi}}{\text{ hr}}
$
no answer given so hope this is it..:cool:
assume "rev" not a unit measure but doesn't cancel out so its not carried thru..

Yep. That is it.
And indeed, "rev" is not a unit measure - it's dimensionless.
Or if you want, you have $2\pi \cdot 13 \text{ in/rev}$, making it cancel out nicely.
 
Re: speed of a Bicycle

I like Serena said:
Yep. That is it.
And indeed, "rev" is not a unit measure - it's dimensionless.
Or if you want, you have $2\pi \cdot 13 \text{ in/rev}$, making it cancel out nicely.

cool tip..

I am going to start another thread with one that is:confused: to me. I don't understand RAD...
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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