Inverse of a function (Gr 12 math)

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SUMMARY

The discussion focuses on finding points on the graphs of transformed functions, specifically the inverse of a function and its transformations. The first transformation, \( y = f\left(-\frac{1}{2}x\right) + 1 \), leads to the point \(\left(-\frac{1}{2}a, b + 1\right)\) when \(f(a) = b\). The second transformation, \( y = f^{-1}(x) + 2 \), requires understanding that if \(f(a) = b\), then \(f^{-1}(b) = a\), resulting in the point \((b, a + 2)\). The key takeaway is the importance of correctly applying the definitions of function inverses and transformations.

PREREQUISITES
  • Understanding of function notation and transformations
  • Knowledge of inverse functions and their properties
  • Familiarity with algebraic manipulation of equations
  • Basic concepts of domain and range in functions
NEXT STEPS
  • Study the properties of inverse functions in detail
  • Practice transforming functions and finding their inverses
  • Explore graphical representations of functions and their inverses
  • Learn about the implications of function transformations on their graphs
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Students studying Grade 12 mathematics, particularly those focusing on functions and their inverses, as well as educators seeking to clarify these concepts for their students.

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Inverse of a function.. (Gr 12 math) [SOLVED]

Homework Statement


If point (a,b) is on the line of y = f(x), what poin must be on the line of:

1. y = f\left(-\frac{1}{2}x\right)+1
2. *Trouble question* y=f^{-1}(x)+2


Homework Equations





The Attempt at a Solution



My answer for the first was : \left(-\frac{1}{2}a, b+2\right)

the second one bothers me... i know you have to swap the domain and range. but normally the questions i get are if y = 2x + 3, what is the inverse of the function. I then swap the x and y to get x = 2y + 3 then rearrange to end up with the answer y= (x-3)/2 but i don't really know where to start here...

I don't have an answer key for this worksheet. but what do i do, do i just go x = y +2 and do the reverse, then i would answer (a-2, b+2)? This is really bugging me.

Regards,
Senjai
 
Last edited:
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Senjai said:

Homework Statement


If point (a,b) is on the line of y = f(x), what poin must be on the line of:

1. y = f\left(-\frac{1}{2}x\right)+1
2. *Trouble question* y=f^{-1}(x)+2


Homework Equations





The Attempt at a Solution



My answer for the first was : \left(-\frac{1}{2}a, b+2\right)
No. You are completely misunderstanding the point of the problem. All you know about f is that f(a)= b so to be able to find f((1/2)x) at all, you must have (1/2)x= a. Now what is x? And, since f((1/2)x)= f(a)= b, what is y?

the second one bothers me... i know you have to swap the domain and range. but normally the questions i get are if y = 2x + 3, what is the inverse of the function. I then swap the x and y to get x = 2y + 3 then rearrange to end up with the answer y= (x-3)/2 but i don't really know where to start here...

I don't have an answer key for this worksheet. but what do i do, do i just go x = y +2 and do the reverse, then i would answer (a-2, b+2)? This is really bugging me.
What happened to f? This has nothing at all to do with "x=y+2" or "y= x=- 2".
Since all you know about f is that f(a)= b, all you know about f-1 is that f-1(b)= a. So in order to say anything at all about f-1(x), you must have x= b. In that case, f-1(x)= f-1(b)= a. So what is f-1(x)+ 2.

Notice that in neither of these questions are you asked anything very general- just to determine a single point on the graph.

Regards,
Senjai
 

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