Is -1/(2sin²x) + C the antiderivative of cos(x)/sin³(x)?

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laker_gurl3
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was just wondering if this was the right answer..
take the anti-derivative of:

cosx dx / sin^3x

i got
-1/2(sinx)^-2 + C
is that right?
 
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Just a tip, if your not sure, take the derivative and check if you get the original function.
 
Maple?? Maple?? ! Let u= sin x. Then du= cos du and the integrand becomes
[tex]\frac{cos x}{sin^3 x}dx= \frac{1}{u^3}du= u^{-3}du[/tex]

The anti-derivative of that is [tex]\frac{1}{-3+1}u^{-3+1}+C= \frac{1}{2}u^{-2}+C= \frac{1}{2}\frac{1}{sin^2 t}+C[/tex]

Good job, laker_gurl3