Is a 2.126 Diameter A2 Tool Steel Shaft Sufficient for 2,500 ft/lbs of Torque?

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The discussion centers on the adequacy of a 2.126" diameter A2 tool steel shaft, hardened to Rc 48-52, for withstanding a maximum peak torque of 2,500 ft/lbs. Participants emphasize the importance of calculating the polar moment of inertia (J) and allowable shear stress, which typically ranges from 12 ksi to 20 ksi for tool steel. Additionally, they highlight the necessity of considering fatigue loading and suggest following a comprehensive shaft design process, referencing Shigley's Mechanical Engineering Design for further guidance.

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Indiana Dave
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Good folks, I need some guidance.

I have a shaft in a machine, hardened A2 tool steel- Rc 48-52 that is 2.126" dia., 3" long.

This shaft will see a maximum peak torque loading of 2,500 ft/lbs.

I am hopelessly mired in calculations I do not trust. Can someone weigh in? Is this shaft section satisfactory?

Thanks!
 
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Try this approach:

Torque = J * allowable stress / radius

J = polar moment of inertia = 1/2 * PI * radius^4

allowable shear stress for tool steel - you will need to look up, but probably somewhere between 12 ksi to 20 ksi. If your tool steel is HRC, the yield may be much higher. See if you have MTR for the steel.
 
Last edited:
Hi I'm new here. i just came across this post.

edgepflow,no offence but won't that method account for only static loading?
You might have to go through the whole shaft design process (Free Body Force diagrams-->BM and shear force diagrams-->stress calculation using endurance limit etc.) for fatigue loading(cyclic stress) since it will be mounted in a machine. I'd refer to Shigley's Mechanical Engineering Design book ISBN: 0−390−76487−6. To be honest i experienced MANY problems myself, when i designed my first shaft alone, so i know how it feels.
 

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