Is Algebraic Equality True? $\frac{x+y}{(x^2+y^2)} = \frac{1}{x+y}$

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Discussion Overview

The discussion revolves around the algebraic equality of the expression $\frac{x+y}{(x^2+y^2)} = \frac{1}{x+y}$. Participants are exploring whether this equality holds true, with a focus on algebraic correctness and potential misconceptions.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant questions the algebraic correctness of the equality.
  • Another participant asserts that the equality is not correct.
  • A third participant provides a specific example using numbers, questioning if $\frac{5}{13}$ is equal to $\frac{1}{5}$ as a way to illustrate the original claim.
  • A later reply identifies a common misconception referred to as the "freshman's dream," which involves the incorrect assumption that $(x+y)^2 = (x^2+y^2)$.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are conflicting views on the correctness of the algebraic equality presented.

Contextual Notes

The discussion highlights potential misunderstandings related to algebraic identities and the specific conditions under which the equality might hold or fail.

whatlifeforme
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Is \frac{x+y}{(x^2+y^2)} = \frac{1}{x+y}

would that be algebraically correct?
 
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whatlifeforme said:
Is \frac{x+y}{(x^2+y^2)} = \frac{1}{x+y}

would that be algebraically correct?

No, it is not.
 
whatlifeforme,
Would this be correct?

$$ \frac{2 + 3}{2^2 + 3^2} = \frac{1}{2 + 3}$$

More simply, this is asking whether 5/13 is equal to 1/5.
 
And I want to add that your mistake is the so-called "freshman's dream", that is, the incorrect idea that ##(x+y)^2=(x^2+y^2)##, which it does not.
 

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