- #1
FallenApple
- 566
- 61
I can see how it would be conserved for the situation of a star turning into a white dwarf since the object is just contracting. Just like the classic ice skater example.
But what about a super nova? Say a star with spin up goes supernova and that the remaining black hole also has spin up but is rotating much faster.
Does that mean that the remaining fragments will have a total angular momentum vector that is pointing down? Let's assume that not only is the spin rate faster, but the angular momentum vector itself is larger upwards for the black hole after supernova compared to the upwards vector before as a star. Mathematically, we need an angular momentum vector that is pointing down so that the vector sum is the same as the angular momentum pre-explosion.
Also, conservation makes sense, since there is no external torque form anywhere else in the universe during the implosion/explosion.
But what would this mean? Does it mean that on average, the flying fragments would have spin down?
But what about a super nova? Say a star with spin up goes supernova and that the remaining black hole also has spin up but is rotating much faster.
Does that mean that the remaining fragments will have a total angular momentum vector that is pointing down? Let's assume that not only is the spin rate faster, but the angular momentum vector itself is larger upwards for the black hole after supernova compared to the upwards vector before as a star. Mathematically, we need an angular momentum vector that is pointing down so that the vector sum is the same as the angular momentum pre-explosion.
Also, conservation makes sense, since there is no external torque form anywhere else in the universe during the implosion/explosion.
But what would this mean? Does it mean that on average, the flying fragments would have spin down?