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What is Black Hole Complementarity?
The discussion revolves around the concept of Black Hole Complementarity, exploring its definitions, implications, and the relationship between different observers in the context of black holes and Hawking radiation. The scope includes theoretical interpretations and potential consequences of the principle.
Participants express differing views on the relationship between Hawking and Unruh radiation, with some suggesting they are equivalent while others maintain they are distinct. The discussion remains unresolved regarding the implications and consequences of Black Hole Complementarity.
Participants highlight the complexity of the definitions and the role of the event horizon in breaking correlations between events inside and outside the black hole, indicating potential limitations in understanding the implications of the principle.
hellfire said:I think I can tell you what it is, but I cannot tell you what the consequences are. The principle is based on the fact that Hawking radiation arises from the different definitions of particles and vacuum for a freely falling observer and for a locally accelerated observer located at a constant radius from the black hole. The observer at a constant radius perceives the black hole exerting a thermal radiation (Hawking radiation) and he can consider the black hole to be at a specific temperature. He also observers matter falling into the black hole. The freely falling observer just crosses the horizon towards the singularity without measuring anything of that. Black hole complementarity means an equivalence of both descriptions. Now, regarding consequences, note that this is not just like two different descriptions from two different coordinate systems, because a horizon exists which breaks any possible correlation between events inside and outside the black hole. May be someone can tell us more about this.
hellfire said:Unruh radiation is not a gravitational effect. An observer at a fixed position in Schwarzschild spacetime would detect Hawking radiation.
Yes. Because of the principle of equivalence.selfAdjoint said:Um, aren't they really the same thing when you come right down to it? Accelerated observer in a relativistic quantum vacuum?