cdux
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Considering e is the limit->+oo of (1+1/n)^n, then is e "what you get if you wait for the least gain, by waiting for the most amount of time"? Something like "e is the patience number".
No explanation?arildno said:Hmm..No.
You might wish to look at, for example, the actual limit of, for example, (1+1/(3n))^(2n)cdux said:No explanation?