MHB Is Expanding (x - a)^4 Necessary for Factoring 64(x - a)^4 - x + a?

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Factor: 64(x - a)^4 - x + a

Must I expand (x - a)^4 as step 1?
 
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As a first step, I would write:

$$64(x-a)^4-x+a=64(x-a)^4-(x-a)$$

Next factor out $x-a$, and the other factor will be the difference of cubes. :D
 
I can take it from here.
 
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