Is f(x) = x^2 on [-5,10] an even function?

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Discussion Overview

The discussion centers on whether the function f(x) = x^2, defined on the interval [-5,10], qualifies as an even function. Participants explore the implications of the function's domain on its classification as even or odd.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant states that a function is even if f(-x) = f(x) for any x in its domain, questioning if this applies to f(x) = x^2 on [-5,10].
  • Another participant argues that an even or odd function must be defined on a symmetric domain, asserting that [-5,10] is not symmetric.
  • A later reply poses a question about the specific values of the function at f(8) and f(-8), implying a consideration of symmetry in function values.

Areas of Agreement / Disagreement

Participants express disagreement regarding the classification of the function as even, with differing views on the necessity of a symmetric domain.

haoku
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f(x) is an even function if f(-x) = f(x) for any x in the domain of f.
Now I say that f(x) = x^2 is defined on [-5,10]. Can I say f(x) is an even function?
 
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Last edited:
No, you can't.
An odd or even function must be defined on a symmetric domain.
But [-5,10] is not symmetric.
 
Is f(8)= f(-8)?
 

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