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No you can't. At least, not in a uniform field.Mentz114 said:Regardless of what any theory says - gravity is a force - you can feel it.
EDIT: Never mind, I see that I am 25 posts too slow
But I second D H et al.No you can't. At least, not in a uniform field.Mentz114 said:Regardless of what any theory says - gravity is a force - you can feel it.
But I second D H et al.You can do Lagrangian and Hamiltonian mechanics using conservation and symmetry concepts and without needing the concept of forces.Austin0 said:COuldnt you look at particle collisions and accelerations as transfers of momentum with conservation but without any need for a concept of force?
espen180 said:A measuring device of an electrostatic field probes the field with a known charge and measures the force acting on it, for example using a spring. It is possible to construct a similar apparatus for probing the gravitational field using a spring and a known mass, but it will not work. you will have created an accelerometer, which is unable to differenciate between gravitational acceleration and motional acceleration (the two are equivalent in GR). Therefore, such an apparatus will measure that it is being accelerated away from the center of the Earth when you hold it, standing on the surface.
Calimero said:You are failing to show how that differs from charge in electrostatic field.
espen180 said:The fact that the magnitude of a mass is irrelevant to its acceleration is the big difference.
DaleSpam said:Hi Calimero, I am with espen180 on this. The fact that the gravitational force is proportional to the mass is what allows it to be removed by choice of reference frame. Notice, that the centrifugal and Coriolis forces in a rotating reference frame are also proportional to mass.
Calimero said:I don't argue against that.
If we are talking about forces, then gravitational force does not differ from electrostatic force (assuming attractive charges), other then having constant gravitational/inertial mass ratio, unlike charge/mass ratio which may, or may be not constant in the case of electrostatic force.
I objected against arguments that accelerometers do not register acceleration in free fall, and that one can't feel anything other then weightlessness while in free fall. You really can't exclude gravity from being force based on that.
espen180 said:EM and gravity are different on a much higher level.
The gravitational field can be made to disappear by a coordinate transformation - The EM-field cannot.
Gravity is caused by the stress-energy tensor, a 2-rank tensor - EM is caused by the four-current, a 1-rank tensor
Gravity influences space and time (universal dimensional properties) - EM influences charges and currents (individual particle properties)
The fact that [tex]E^2=\left(pc\right)^2+\left(mc^2\right)^2[/tex] means that everything that has either mass, momentum or energy is influenced by and sources gravity.
espen180 said:GM takes things like accelerometer measurements very seriously. If you don't rely on your measurements and observations, what can you rely on?
Calimero said:We are here arguing semantics. Point is: you can talk about gravity as a force, and easily explain why accelerometers do not register acceleration. That is all.
I don't understand that either. They seem to have much more in common with the centrifugal and Coriolis forces to me.Calimero said:I assumed that you will understand context in which I meant that they don't differ.
Doc Al said:No, the contact forces are quite real.
The contact force from the walls of a centrifuge is just as real as the contact force pushing on you in an elevator.
Gravity is a special case. In Newtonian physics, gravity is a real force; in GR, it's an inertial force. But the contact force between objects is real.
espen180 said:Well of course you can say gravity is a force and accelerates objects in GR - in a reference frame that is itself accelerating.