Is it necessary to expand the quantity before factoring the expression?

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Discussion Overview

The discussion revolves around the process of factoring the expression 4a^2b^2 - 9(ab + c)^2 from a precalculus textbook. Participants explore whether it is necessary to expand the quantity (ab + c) before proceeding with the factorization.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that expanding (ab + c) is not necessary and that the expression can be factored directly using the difference of squares.
  • One participant proposes substituting 2ab with x and 3(ab + c) with y to apply the difference of squares formula, leading to the factors (x - y)(x + y).
  • Another participant emphasizes that while further simplification is not required for factorization, it is considered good practice to simplify when possible.
  • There is a discussion about whether the goal of the exercise is to factor or to simplify after factoring, with differing opinions on the importance of simplification.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of expanding the quantity before factoring, with some advocating for direct factorization and others emphasizing the potential benefits of simplification. No consensus is reached on the best approach.

Contextual Notes

Participants acknowledge that while they have factored the expression, the discussion remains open regarding the appropriateness of further simplification and the interpretation of the problem's requirements.

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Precalculus by David Cohen, 3rd Edition
Chapter 1, Section 1.3.
Question 29c.

Factor the expression.

4a^2b^2 - 9(ab + c)^2

Must I expand the quantity (ab + c) before factoring?
 
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RTCNTC said:
Precalculus by David Cohen, 3rd Edition
Chapter 1, Section 1.3.
Question 29c.

Factor the expression.

4a^2b^2 - 9(ab + c)^2

Must I expand the quantity (ab + c) before factoring?

You need not

you get as $(2ab)^2 - (3(ab+c))^2$ difference of 2 squares and now you should be able to proceed
 
(2ab)^2−(3(ab+c))^2

I will let 2ab = x and [3(ab + c)] = y.

x^2 - y^(2)

(x - y)(x + y)

Back-substitute now.

[(2ab - 3(ab + c)][(2ab + 3(ab + c)]

Correct?
 
RTCNTC said:
(2ab)^2−(3(ab+c))^2

I will let 2ab = x and [3(ab + c)] = y.

x^2 - y^(2)

(x - y)(x + y)

Back-substitute now.

[(2ab - 3(ab + c)][(2ab + 3(ab + c)]

Correct?

Yes, although I would distribute within the factors and then combine like terms. :D
 
I thought about distributing within the factors and combining like terms but the question is asking to factor not to simplify after factoring.
 
RTCNTC said:
I thought about distributing within the factors and combining like terms but the question is asking to factor not to simplify after factoring.

Well, technically, further simplification is not required to complete the goal of factorization...you have indeed factored...but in my opinion, it's just good practice to simplify whenever possible.
 
MarkFL said:
Well, technically, further simplification is not required to complete the goal of factorization...you have indeed factored...but in my opinion, it's just good practice to simplify whenever possible.

I agree.
 

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