Is My Average Value Calculation for Function g(x) on Interval [-π, 0] Correct?

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Mr Davis 97
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Homework Statement


The average value of the function ##g(x) = 3^{\cos x}## on the closed interval ##[- \pi, 0]## is:

Homework Equations

3. The attempt at the solution

I used the standard method for finding average value over an interval with my calculator using an integral, and got the answer 1.3528. However, the doesn't correspond to any of the possible answers given in my solutions book (30.980, 18.068, 7.593, 4.347, 0.849). What am I doing wrong? Could someone find thr average value and verify that I'm correct?
 
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Mr Davis 97 said:

Homework Statement


The average value of the function ##g(x) = 3^{\cos x}## on the closed interval ##[- \pi, 0]## is:

Homework Equations

3. The attempt at the solution

I used the standard method for finding average value over an interval with my calculator using an integral, and got the answer 1.3528. However, the doesn't correspond to any of the possible answers given in my solutions book (30.980, 18.068, 7.593, 4.347, 0.849). What am I doing wrong? Could someone find thr average value and verify that I'm correct?
What @axmls said.

Let me add a question. Are you sure you posted the exercise and the answers (yours and those from the book) correctly? Neither your answer nor the possible answers in the book is correct.
 
Samy_A said:
What @axmls said.

Let me add a question. Are you sure you posted the exercise and the answers (yours and those from the book) correctly? Neither your answer nor the possible answers in the book is correct.

Actually, the OP's answer is correct; Maple gets the average as 1.325276252 .
 
Ray Vickson said:
Actually, the OP's answer is correct; Maple gets the average as 1.325276252 .
Well, yes and no.

That's why I asked the OP to check his post, including his own answer. He gave 1.3528 as answer, which probably is a typo.
But without seeing anything of his calculations, I couldn't be sure. You are more generous. :oldsmile:
 
Samy_A said:
Well, yes and no.

That's why I asked the OP to check his post, including his own answer. He gave 1.3528 as answer, which probably is a typo.
But without seeing anything of his calculations, I couldn't be sure. You are more generous. :oldsmile:

OK: I see that I was not careful enough, and I had needed to clean my glasses.