MHB Is my solution for forming 10-letter words with restrictions correct?

  • Thread starter Thread starter evinda
  • Start date Start date
evinda
Gold Member
MHB
Messages
3,741
Reaction score
0
Hello! (Wave)

I am given the following exercise:

How many words with $10$ lettrers can be formed with the letters $A,B,C$, when it is not allowed that the word begins or ends with two same letters.

I thought that the number of words is $$3^{10}-2 \cdot 3^9+3^8$$

because:

Number of words without restrictions: $3^{10}$

Number of words when the two first letters are the same: $3^{9}$

Number of words when the two last letters are the same: $3^{9}$

Number of words when the first two and the last two are the same: $3^{8}$Could you tell if it's right?Or am I wrong? :confused:
 
Physics news on Phys.org
I think your solution is correct.
 
Evgeny.Makarov said:
I think your solution is correct.

Nice! Thank you very much! (Clapping) (Clapping)
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Back
Top