Is (n^2+3)(n^2+15) divisible by 32 for odd positive integers n?

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SUMMARY

The expression (n²+3)(n²+15) is proven to be divisible by 32 for all odd positive integers n through mathematical induction. The base case for n=1 yields a product of 64, confirming divisibility by 32. The inductive step involves assuming the expression holds for n=k, leading to the expression for n=k+1, which simplifies to show that the additional terms also maintain divisibility by 32. This confirms the hypothesis for all odd positive integers.

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sushichan
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Homework Statement


Prove that (n2+3)(n2+15) is divisible by 32 for all odd positive integers n.

Homework Equations


I suppose we are supposed to use mathematical induction since it is in that chapter, but the following questions specifically state that we should use induction but this question doesn't.

The Attempt at a Solution


n=1
(1+3)(1+15)=64=2*32​
n=k
(k2+3)(k2+15)=32A, A∈ℝ​
n=k+1
⇒((k+2)2+3)((k+2)2+15)
= (k2+3)(k2+15) + 8k3+24k2+104k+88
= 32A + 8(k3+3k2+13k+11)​
 
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sushichan said:
A∈ℝ
You don't mean that.
sushichan said:
n=k+1
Think about that choice again. Note that it says:
sushichan said:
all odd positive integers n
 

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