Is n Prime if Zero Products and Unique Solutions Exist in Modulo n Arithmetic?

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SUMMARY

The discussion centers on proving two conditions that characterize prime numbers in the context of modulo n arithmetic. Specifically, it establishes that n is prime if and only if for any a, b in Zn, the equation ab=0 implies either a=0 or b=0. Additionally, it asserts that n is prime if and only if for any non-zero a, the equation ab=ac leads to b=c. The proofs hinge on the definitions of divisibility and the properties of prime numbers.

PREREQUISITES
  • Understanding of modulo arithmetic and the notation Zn
  • Familiarity with prime number definitions and properties
  • Knowledge of divisibility and greatest common divisor (gcd)
  • Basic proof techniques in number theory
NEXT STEPS
  • Study the properties of prime numbers in number theory
  • Learn about the implications of gcd(a, n) = 1 in relation to coprimality
  • Explore the concept of unique factorization in integers
  • Investigate the structure of the multiplicative group of integers modulo n
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Mathematicians, students of number theory, and anyone interested in the foundational properties of prime numbers and their applications in modular arithmetic.

guyfromnola
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I'm having some trouble addressing the following two questions in a text I am going through:

1. Show that n is a prime number iff whenever a,b ∈ Zn with ab=0, we must have that a=0 or b=0.

2. Show that n is a prime number iff for every a,b,c ∈ Zn satisfying a not =0, and ab=ac, we have that b=c.

There were some other similar questions that addressed showing two numbers are relatively prime by showing that gcd(a,n)=1, which was a little difficult to start, but I think I managed to get through them. However, I am stuck with these. Not sure how to begin to prove.

Any help is appreciated.
 
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guyfromnola said:
However, I am stuck with these. Not sure how to begin to prove.

Begin by expanding the definitions.

For 1:
ab = 0 (mod n) exactly when n | ab
a = 0 (mod n) exactly when n | a
b = 0 (mod n) exactly when n | b

So the question becomes:
Show that n is a prime number iff whenever n | ab, we must have that n | a or n | b.

That is, you need to show:
a. If n is prime and n | ab, either n | a or n | b.
b. If n is not prime, then there is some pair (a, b) with n ∤ a, n ∤ b, and n | ab.
 

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