MHB Is $N_{10}$ even or odd?

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The discussion centers on determining whether $N_{10}$, which represents the number of ordered tuples of positive integers satisfying the equation $1/a_1 + 1/a_2 + \ldots + 1/a_n = 1$, is even or odd. This problem is a part of the Problem of the Week (POTW) and was previously featured in the 1997 William Lowell Putnam Mathematical Competition. Despite the challenge, no participants provided answers to this week's question. The solution, credited to Kiran Kedlaya and his associates, is expected to clarify the parity of $N_{10}$. The thread highlights the ongoing interest in mathematical competitions and problem-solving.
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Here is this week's POTW:

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Let $N_n$ denote the number of ordered $n$-tuples of positive integers $(a_1,a_2,\ldots,a_n)$ such that $1/a_1 + 1/a_2 +\ldots +1/a_n=1$. Determine whether $N_{10}$ is even or odd.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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Re: Problem Of The Week # 230 - Aug 25, 2016

This was Problem A-5 in the 1997 William Lowell Putnam Mathematical Competition.

No one answered this week's POTW. The solution, attributed to Kiran Kedlaya and his associates, follows:

We may discard any solutions for which $a_1 \neq a_2$, since those come in pairs; so assume $a_1 = a_2$. Similarly, we may assume that $a_3 = a_4$, $a_5 = a_6$, $a_7 = a_8$, $a_9=a_{10}$. Thus we get the equation
\[
2/a_1 + 2/a_3 + 2/a_5 + 2/a_7 + 2/a_9 = 1.
\]
Again, we may assume $a_1 = a_3$ and $a_5 = a_7$, so we get $4/a_1 + 4/a_5 + 2/a_9 = 1$; and $a_1 = a_5$, so $8/a_1 + 2/a_9 = 1$. This implies that $(a_1-8)(a_9-2) = 16$, which by counting has 5 solutions. Thus $N_{10}$ is odd.