MHB Is R an Identity Relation on A?

  • Thread starter Thread starter oriel1
  • Start date Start date
  • Tags Tags
    Identity Relation
oriel1
Messages
8
Reaction score
0
Let A= {1,2,3}.
Let R= {<1,1>,<2,2>}.

I(A) (Identity Realtion) on A >(def)> {<x,x>|x $$\in$$ A}
So that mean : $$\forall$$ <x,x> x $$\in$$ A
(That how I understood it)

My question:
Is R is identity relation on A ?

Thank you !
 
Physics news on Phys.org
No. Think about (3,3).
 
Deveno said:
No. Think about (3,3).
Ok Actually R={<1,1>,<2,2>,<3,3>} is identity relation on A for sure.
But what prevent from R= {<1,1>,<2,2>} to bo identity on A?
It not writed $$\forall$$ x $$\in$$ A.
 
The definition (yours, not mine) says:

$I(A) = \{(x,x)\mid x \in A\}$.

However, $3 \in A = \{1,2,3\}$, but $(3,3) \not\in R$.

That is, $(3,3)$ is a pair with $3 \in A$, and thus $(3,3)$ fulfills the requirements to be an element of $I(A)$. Most texts define the identity relation as the smallest possible equivalence relation on a given set, and your relation fails the reflexive test.
 
Thank you. now i understand it.
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...

Similar threads

Back
Top