MHB Is the adjunction space $X \cup_f Y$ normal for closed $A$ and continuous $f$?

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The discussion centers on proving that the adjunction space $X \cup_f Y$ is normal when $X$ and $Y$ are normal topological spaces, $A$ is a closed subset of $X$, and $f: A \to Y$ is continuous. A hint provided suggests considering the Tietze extension property as part of the proof. Despite the challenge, no responses were given to the problem of the week. The original poster shares their solution below for reference. The topic emphasizes the relationship between normal spaces and the properties of adjunction spaces in topology.
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Here is this week's POTW:

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Let $X$ and $Y$ be normal topological spaces. Suppose $A$ is a closed subset of $X$ and $f : A \to Y$ is a continuous map. Prove that the adjunction space $X \cup_f Y$ is normal.
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Here's a hint: Consider the Tietze extension property.
 
No one answered this week’s problem. You can read my solution below.

It suffices to show that $X \cup_f Y$ has the Tietze extension property. Let $B$ be a closed subset of $X \cup_f Y$; let $p : X \cup Y \to X\cup_f Y$ be the projection map. Given a continuous map $g : B \to \Bbb R$, the restriction of $g$ to the closed set $p^{-1}\cap B$, $g_B: p^{-1}(B) \cap Y \to \Bbb R$, has a continuous extension $\phi : Y \to \Bbb R$ by normality of $Y$. The composition $g_B\circ f : A \to \Bbb R$ agrees with $\phi$ on the intersection $A\cap [p^{-1}(B) \cap X]$, so there is a natural extension $\phi : A \cup [p^{-1}(B) \cap X] \to \Bbb R$. Normality of $X$ gives a continuous extension of $\phi$, $\Phi : X \to \Bbb R$. Now $\Phi(a) = g_B(f(a))$ for all $a\in A$, so by the universal property of quotients $\Phi$ and $g_B$ induce a unique continuous map $G : X\cup_f Y \to \Bbb R$. This map extends $g$.