MHB Is the Left-Adjoint Functor Preserving Colimits of Functors?

  • Thread starter Thread starter Euge
  • Start date Start date
  • Tags Tags
    2015
Click For Summary
The discussion centers on proving that a left-adjoint functor preserves colimits. Specifically, if a functor F from category D to category C has a colimit in C, then applying the left-adjoint functor L to this colimit results in a colimit of the composition L ∘ F in category C'. The problem emphasizes the relationship between left-adjoint functors and colimits, highlighting the structural properties of categories. No solutions were provided by participants, but one solution is available for reference. The discussion underscores the importance of understanding functorial relationships in category theory.
Euge
Gold Member
MHB
POTW Director
Messages
2,072
Reaction score
245
Here's this week's problem!

_____________

Problem. Let $L : \mathcal{C} \to \mathcal{C}$ be a left-adjoint functor from category $\mathcal{C}$ to category $\mathcal{C'}$. Show that if $F : \mathcal{D} \to \mathcal{C}$ is a functor such that $\operatorname{colim} F$ is an object of $\mathcal{C}$, then $L(\operatorname{colim} F)$ is a colimit of $L \circ F : \mathcal{D} \to \mathcal{C'}$.

_____________
Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
Physics news on Phys.org
No one answered this week's problem. You can find my solution below.

If $\mathcal{C}\overset{L}{\underset{R}{\rightleftarrows}}\mathcal{C'}$ is an adjunction, then for every object $Y$ in $\mathcal{C'}$,

\begin{align}
\operatorname{Hom}_{\mathcal{C}}(L(\operatorname{colim} F, Y) &\approx \operatorname{Hom}_{\mathcal{C'}}(\operatorname{colim} F, RY)\\
&\approx \operatorname{colim} \operatorname{Hom}_{\mathcal{C'}}(F, RY)\\
&\approx \operatorname{colim} \operatorname{Hom}_{\mathcal{C}}(L\circ F, Y)\\
&\approx \operatorname{Hom}_{\mathcal{C}}(\operatorname{colim}(L\circ F), Y).
\end{align}

Hence by Yoneda's lemma,

$$L(\operatorname{colim} F) \approx \operatorname{colim}(L\circ F).$$
 

Similar threads

Replies
1
Views
3K
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
Replies
1
Views
2K
Replies
1
Views
3K
Replies
1
Views
2K