Is the Left-Adjoint Functor Preserving Colimits of Functors?

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    2015
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SUMMARY

The discussion centers on the proof that a left-adjoint functor \( L : \mathcal{C} \to \mathcal{C'} \) preserves colimits of functors. Specifically, if \( F : \mathcal{D} \to \mathcal{C} \) is a functor such that the colimit \( \operatorname{colim} F \) exists in category \( \mathcal{C} \), then \( L(\operatorname{colim} F) \) is confirmed to be a colimit of the composed functor \( L \circ F : \mathcal{D} \to \mathcal{C'} \). This conclusion is pivotal for understanding the behavior of left-adjoint functors in category theory.

PREREQUISITES
  • Understanding of category theory concepts, specifically functors and colimits.
  • Familiarity with left-adjoint and right-adjoint functors.
  • Knowledge of the notation and terminology used in category theory.
  • Basic comprehension of the structure of categories \( \mathcal{C} \) and \( \mathcal{C'} \).
NEXT STEPS
  • Study the properties of left-adjoint functors in more depth.
  • Explore examples of colimits in various categories.
  • Learn about right-adjoint functors and their relationship with left-adjoint functors.
  • Investigate the implications of functor composition in category theory.
USEFUL FOR

This discussion is beneficial for mathematicians, particularly those specializing in category theory, as well as students and researchers looking to deepen their understanding of functorial relationships and colimit preservation.

Euge
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Here's this week's problem!

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Problem. Let $L : \mathcal{C} \to \mathcal{C}$ be a left-adjoint functor from category $\mathcal{C}$ to category $\mathcal{C'}$. Show that if $F : \mathcal{D} \to \mathcal{C}$ is a functor such that $\operatorname{colim} F$ is an object of $\mathcal{C}$, then $L(\operatorname{colim} F)$ is a colimit of $L \circ F : \mathcal{D} \to \mathcal{C'}$.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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No one answered this week's problem. You can find my solution below.

If $\mathcal{C}\overset{L}{\underset{R}{\rightleftarrows}}\mathcal{C'}$ is an adjunction, then for every object $Y$ in $\mathcal{C'}$,

\begin{align}
\operatorname{Hom}_{\mathcal{C}}(L(\operatorname{colim} F, Y) &\approx \operatorname{Hom}_{\mathcal{C'}}(\operatorname{colim} F, RY)\\
&\approx \operatorname{colim} \operatorname{Hom}_{\mathcal{C'}}(F, RY)\\
&\approx \operatorname{colim} \operatorname{Hom}_{\mathcal{C}}(L\circ F, Y)\\
&\approx \operatorname{Hom}_{\mathcal{C}}(\operatorname{colim}(L\circ F), Y).
\end{align}

Hence by Yoneda's lemma,

$$L(\operatorname{colim} F) \approx \operatorname{colim}(L\circ F).$$
 

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