Is the vectorial representation of the Lorentzian Group unitary?

  • Thread starter IRobot
  • Start date
  • #1
87
0

Main Question or Discussion Point

I am 99% sure it is not, but I would like to hear that from someone else to be more serene.
 

Answers and Replies

  • #3
87
0
Thanks I already was thinking with that argument, I did the calculation of [itex] \Lambda \Lambda ^\dagger[/itex] for some random Lorentz Matrix. Was just looking for a confirmation.
 
Last edited:
  • #4
dextercioby
Science Advisor
Homework Helper
Insights Author
12,991
543
It's because the Lorentz group (or its component connected to the identity) is non-compact. It's a classical result, a proof of which can be found in Cornwell's compendium.
 

Related Threads on Is the vectorial representation of the Lorentzian Group unitary?

Replies
5
Views
615
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
9
Views
3K
Replies
4
Views
1K
Replies
2
Views
2K
Replies
4
Views
243
Replies
5
Views
3K
Replies
9
Views
838
Replies
6
Views
1K
Top