Is there a known formula for integrating cos^5x sin^5x?

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johnhuntsman
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∫cos^5 x sin^5 x dx

I thought I would try to solve this by first doing:

∫(1 - sin^2 x) cos^3 x sin^5 x dx

but would like to know if that's right.

[Edit] Is the answer something like (sin^6 x) / 6 - (sin^8 x) / 4 + (sin^10 x) / 10 ?[Edit]
 
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johnhuntsman said:
∫cos^5 x sin^5 x dx

I thought I would try to solve this by first doing:

∫(1 - sin^2 x) cos^3 x sin^5 x dx

but would like to know if that's right.

[Edit] Is the answer something like (sin^6 x) / 6 - (sin^8 x) / 4 + (sin^10 x) / 10 ?[Edit]
How did you get it?

Take the derivative, to check it.


Don't forget the constant of integration.
 
SammyS said:
How did you get it?

I split up the cos^3 x just like I did the cos before. Then used u substitution.

SammyS said:
Take the derivative, to check it.

I did. Thanks, everything's okey dokey now : D