Is There an ISW Potential During the Matter Dominant Era?

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Mordred
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I've been reading reading an older article on ISW (integrated Sache-wolfe effect). One line struck me as odd in the paper.
http://arxiv.org/abs/0801.4380v2

on page two the line " In particular, we know that during the matter dominated era the gravitational potential stays constant "

I can understand that during the matter dominant era, the cosmological constant effect is greatly reduced. However wouldn't there be an ISW potential due to dynamics of the matter dominant era?
 
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The gravitational potential referred to is the analog Newtonian potential associated with the matter perturbations (recall that the Newtonian potential, [itex]\Phi[/itex], vanishes in any homogeneous cosmology). We start with Poisson's Eq.,
[tex]\nabla ^2 \Phi = 4\pi G \delta \rho_m[/tex]
where [itex]\delta \rho_m[/itex] is the matter perturbation. Usually a different quantity is actually solved for -- the density contrast: [tex]\delta = \delta \rho/\bar{\rho}[/tex] where the bar denotes an average, so we instead have
[tex]\nabla^2 \Phi = 4\pi G \bar{\rho}\delta_m[/tex] In order to solve Poisson's equation, we work in Fourier space so that the [itex]\nabla^2[/itex] brings down two factors of the physical wavenumber, [itex](k/a)^2[/itex]. Putting it all together we have
[tex]\Phi_k = 4 \pi G\left(\frac{a^2}{k^2}\right)\bar{\rho}\delta_{m,k}[/tex]
Now, during matter domination we know that [itex]\bar{\rho} \sim a^{-3}[/itex], and there is a growing mode [itex]\delta_k \sim a[/itex] (this is found by solving the perturbation equation in Newtonian gauge). We find then
[tex]\Phi_k = 4\pi G \left(\frac{a^2}{k^2}\right) \frac{a}{a^3} = const[/tex].

EDIT: The important conceptual point here is that [itex]\Phi[/itex] is not associated with the background density, [itex]\rho[/itex] (or really [itex]\bar{\rho}[/itex]), but with the perturbations. In a homogeneous cosmology, there is no gravitational potential/field.
 
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Thanks a ton that excellent explanation, answered the question beautifully.
 

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