Is there any numbers with infinite digits

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There are no numbers with infinite digits in their integer form, as integers are finite by definition. However, certain decimal representations can be infinite, such as the repeating decimals of rational numbers. Rational numbers can have infinite decimal expansions but are still finite in their integer representation. Irrational and transcendental numbers, like the square root of 2 or pi, also have infinite decimal expansions but cannot be expressed as simple fractions. The discussion clarifies that while infinite sequences exist, they do not correspond to traditional numerical values.
amature83
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Hello,

Is there any number with infinite digits (e.g. 34343329...) or just the decimal representation of a number could be infinite (e.g. 1/9 = .1111...)?

I appreciate your reply.

Thanks
ME
 
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If you mean integers (whole numbers, with no decmal places) then yes there are an infinite number of them. You can see this because any number you give me I can always add another digit on the end.

There are a few types of decimals (real numbers) that also go on for ever.

Rational numbers are those that you can write as a fraction like 1/3

Irrational numbers are those that go on for ever but cannot be written as a shorter fraction. Numbers like the sqrt(2), you can write this as an equation but not a fraction.

Transcendental numbers are the 'most infinite' if you like. Not only do these numbers go on for ever but you cannot write numbers like pi or 'e' as any fraction or equation that isn't infinite.
 
If you mean integers (whole numbers, with no decmal places) then yes there are an infinite number of them. You can see this because any number you give me I can always add another digit on the end.

I think I didn't make the question clear. I am sorry about that..
I ask about the infinite string of digits, say infinite string of 1's: 11111... What is that number? I think it's not natural because the construction of N by successor (using Peano Arithm.) would never get us the "infinite" string. So, could we call it rational? My doubts about calling it rational is that -as far as I understand- in rationals the decimal expansion could be an infinite string strings but not the number itself.

ME
 
No, there are no integers whose expression in base 10 requires an infinite number of digits. Specifically, 10n is an unbounded sequence. That means that, given any integer, a, there exist an integer N so that a< 10N. a has less than N decimal places.

A "rational number" is defined as a number of the form m/n where m and n are integers (and n is not 0) so, no, there are no rational numbers, or even irrational numbers, that have an infinite string of digits in front of the decimal point.
 
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mgb_phys & HallsofIvy: thanks a lot
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

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