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I Is this condition for infinite roots wrong?

  1. Jun 6, 2016 #1
    I found a strange theorem and a doubtful method in Stroud's book "Engineering mathematics":
    asymptote.JPG
    I think, every polynomial equation will have two infinite roots (at +infinity and -infinity).
    I also think that this method of the determination of an asymptote gives wrong results if f(x) is a polynomial with a high degree.
    Are the theorem and the method in this book wrong?
     
    Last edited: Jun 6, 2016
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  3. Jun 6, 2016 #2

    mfb

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    That doesn't make sense. Every polynomial has a largest power, so every polynomial has an infinite number of infinite roots?
    Multiplying the equation by yn generates additional solutions for y=0, so it is not surprising that they produce unmathematical solutions for y=0 later. Of course y=0 is a solution to an equation where you multiplied both sides by 0.
     
  4. Jun 6, 2016 #3

    micromass

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    This looks strange but it is kind of correct. It seems the author absolutely butchered the method though. I think what the author likes to do is to compute infinite point and asymptotes in projective geometry using homogeneous coordinates. That uses a method kind of similar to what is in the OP, but the exact explanation of the book is very doubtful.

    Something of the following would be correct though: consider ##y = \frac{x+2}{3x + 2}##. Then we have
    $$3xy + 2y - x - 2 = 0$$
    which gives rise to a homogeneous equation
    $$3xy + 2yz - xz - 2z^2=0.$$
    The points at infinity correspond to ##z=0##, which yields ##x=0## or ##y=0##. This gives us a result that the function has two asymptotes: one parallel to ##x=0## and one parallel to ##y=0## which is indeed correct.
     
  5. Jun 6, 2016 #4

    mathman

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    Statement is strange. if [itex]a_0\ and\ a_1[/itex] are both 0, then the first term should be [itex]a_2x^{n-2}[/itex].
     
  6. Jun 7, 2016 #5
    Thank you all. Stroud's textbook is mostly very good, but I stuck on that place.
     
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