Is this equation solvable and if so, how?

  • #1
xy'=3y+(cosx)x^4

I don't understand how to solve it since it's non-separable.
 

Answers and Replies

  • #2
7
0
y'/x^3-3y/x^4=cosx

d/dx(y/x^3)=cosx

y/x^3=sinx

y=(sinx)x^3
 
  • #3
258
0
I don't understand how to solve it since it's non-separable.

There's more to Differential Equations than just the separable ones. A LOT more.
 
  • #4
70
0
Surely

d/dx(y/x^3)=cosx

y/x^3=sinx+C

y=(sinx+C)x^3

where C is an arbitrary constant.
 

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