Is This Moment Generating Function Expression Correct?

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SUMMARY

The moment generating function (MGF) expression M(t)=1+tμ'_1+...=∑(n=0 to ∞) (E(Y^n)t^n/n!) is correct under specific conditions. The term μ'_n=E(Y^n) is valid when the MGF is exponential, which aligns with the Taylor expansion for a Wiener process. However, this relationship does not universally apply to all distributions. The discussion emphasizes the necessity of understanding the conditions under which the MGF holds true.

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donutmax
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Is the following correct?

[tex]M(t)=1+t\mu'_1+\frac{t^2}{2!}\mu'_2+\frac{t^3}{3!}\mu'_3+... =\sum_{n=0}^{\infty} \frac {E(Y^n)t^n}{n!}[/tex]

where
[tex]\mu'_n=E(Y^n)[/tex]
 
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I think that will only be true if your moment generating function is an exponential - in which case you are just doing a Taylor expansion. This is true for a Wiener process - but I don't think the relation you have holds in general.

Regards,
Thrillhouse86
 
[tex] m_Y(t) = E(e^{ty}) = \int e^{ty} \, dF(y) = \int \sum_{n=0}^\infty \frac{(ty)^n}{n!}\,dF(y) = \sum_{n=0}^\infty \left(\int \frac{(ty)^n}{n!} \, dF(y) \right)[/tex]

What do you get from working with the final form above?
 

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