johne1618 said:
As far as I understand it Hubble's velocity law says that the velocity v of a distant object with respect to us, at the present cosmological time, is given by
v = H_0 * r
where H_0 is the present Hubble constant and r is the distance to the object.
If a distant object is moving at velocity v with respect to us does that mean that proper time measured by an observer near that object is dilated by a gamma factor 1/sqrt(1-v^2/c^2) when measured in our time coordinates?
Vorde said:
I disagree, Vorde.
The present velocities given by Hubble law, for most of the galaxies we can see, are greater than c.
So the gamma factor would involve taking square root of a negative number. It would not make sense as a time dilation factor.
John, the Hubble law as you state it is v = H
0r
where as you say H
0 is the present value of H, and r is the present distance (which you would measure e.g. by radar if you could stop the expansion process) and v is the present rate of change of this present distance.
Most of the galaxies we currently observe have redshift z > 1.5 and any such galaxy would be presently receding at a rate faster than c.
You might find this online calculator interesting
http://www.einsteins-theory-of-relativity-4engineers.com/cosmocalc.htm
Put in a redshift like, for example 1.8 and press "calculate".
Easy to use. Where it says "Distance traveled by the light" this means the distance the light would have traveled in a non-expanding universe, on its own. It is a way of reading off the light travel time. Just read lightyears as years.
Distant galaxies do not normally share the same Lorentz frame---special rel time dilation does not apply to recession rates. It would be terrible if they did since for the most part the rates are superluminal
