Item with Uniform Velocity intersects with Item with Uniform Acceleration

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SUMMARY

The discussion revolves around a physics problem involving a speeder traveling at 120 km/h and a police car accelerating at 7 m/s². The user successfully converted the speed to 33.33 m/s and derived the time of intersection as approximately 9.523 seconds. The distance at which the two vehicles intersect was calculated to be 317.4 meters. The calculations and reasoning presented were confirmed as correct by another forum member.

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QuickSkope
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Solved, thanks :D
 
Last edited:
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QuickSkope said:

Homework Statement


A speeder passes a stationary cop car going 120 km/h. The police car accelerates 7 m/s^2 constantly till he meets up with the speeder. Where do they intersect? What is their time and distance?


Homework Equations


Speeder is car 1, Police car is car 2.
not 100% sure, but I tried using these:
d1 = v * t
V2 = a * t
d2 = 1/2a * t^2

The Attempt at a Solution



Converted 120 km/h to 33+(1/3) m / s.

where does d1 and d2 = the same? When the police car catches up.

Where t is unknown, solve for t:
v*t = 1/2a * t^2
33.33 * t = 1/2(7) * t^2 (substitute values)
33.33t = 3.5t^2 (Do math)
33.33 = 3.5t (remove one t on either side)
9.523 = t

d = v * t

d = 33.33 m/s * 9.523

d = 317.4 m


It feels okay, but I've only been doing physics a short while, I really just need someone to tell me if I am right or wrong. Thanks.

Hi QuickSkope. Welcome to Physics Forums.

Your reasoning and calculations look fine.
 
Okay cool, thanks :D

Thanks for the Welcome, you can probably lock/close this.
 

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