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SUMMARY

The discussion focuses on calculating the work output, work input, and efficiency of a screw pump based on provided parameters. The work output was calculated as 2600J by lifting 130 liters of water 2 meters high. The work input was determined to be 5300J, derived from the force applied and the distance the handle travels. The efficiency of the pump was calculated to be 49%, indicating the ratio of useful work output to work input.

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Homework Statement


A screw pump is turned with a force of 125N. The handle traces a circle with a DIAMETER of 30cm, and is turned 45 times. The pump lifts 130 litres of water 2m high. (1 litre of water = 1kg aka 10N)
What is the work output?
What is the work input?
What is the efficiency of the pump?



Homework Equations





The Attempt at a Solution


For work output, i did: 130 times 10 = 1300N times 2M = 2600J
Work output: 2600J

For work input, i did Pi times .30m = .94m times 45 = 42.4M times 125N = 5300J
Work input: 5300J

Effiiciency: 2600J divided by 5300J = 49%


Is this correct?
 
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