Keplers third law: why kg doesn't cancel in the radius equation

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channel1
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Homework Statement


find the radius
R3=((T2GM/(4∏2))1/3


The Attempt at a Solution


simple enough, my only question is when I plug in T (units: sec) G (units: m/s^2) and M (units: kg) there is nothing to cancel out the kg so my R is not in units of meters...the equation is correct because we were given it in class but what's going on with the units?
 
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channel1 said:

Homework Statement


find the radius
R3=((T2GM/(4∏2))1/3


The Attempt at a Solution


simple enough, my only question is when I plug in T (units: sec) G (units: m/s^2) and M (units: kg) there is nothing to cancel out the kg so my R is not in units of meters...the equation is correct because we were given it in class but what's going on with the units?

Homework Statement




Homework Equations





The Attempt at a Solution


G in this problem isn't an acceleration. It's the gravitational constant G. The units are m^3/(kg*s^2).
 
channel1 said:

Homework Statement


find the radius
R3=((T2GM/(4∏2))1/3

The Attempt at a Solution


simple enough, my only question is when I plug in T (units: sec) G (units: m/s^2) and M (units: kg) there is nothing to cancel out the kg so my R is not in units of meters...the equation is correct because we were given it in class but what's going on with the units?

Homework Statement


That's G, not g :wink:

EDIT: Beaten to the punch!