Kinematics in 1D: Determining Velocity After 0.5s

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SUMMARY

The discussion focuses on calculating the final velocity of a stone thrown vertically with an initial velocity of +7.0 m/s and a constant acceleration of -9.81 m/s² after 0.5 seconds. The relevant equation used is vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time. By substituting the values into the equation, the final velocity is determined to be +2.0 m/s after 0.5 seconds.

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1. A stone is thrown with an initial velocity of +7.0 m/s. The acceleration of the stone is a constant and has the value of -9.81m/s^2.What is the velocity of the stone after 0.5s?



2. Homework Equations
vf=vi+at?
i have no idea



3. The Attempt at a Solution
i can't find the right equation to put this in
 
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What direction is it thrown? Never mind--your title suggests 1D motion, so I presume straight up.

You have the correct equation. Use it!
 

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