Kinematics of attacking seagulls

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SUMMARY

The discussion focuses on the kinematics involved in a seagull's dive to hit a target with a projectile. The seagull dives at a speed of 16 m/s at an angle of 40 degrees below the horizontal, releasing a clam from a height of 8.5 m above the target. The key equations of motion are applied to determine the time it takes for the projectile to reach the target, specifically using the vertical distance and initial velocity components.

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Homework Statement


A flock of seagulls had decided to mount an organized response to the human overpopulation of their favorite beach. One tactic popular among the innovative radicls is bombing the sunbathers with clams. A gull dives with a speed of 16m/sec at an angle of 40 degrees below the horizontal. He releases projectile with his vertical distance above the target, a sunbather's brozned tummy, is 8.5m and scores a bull's-eye


Homework Equations


vi= 16m/s
thata= 40 degrees
yi= 85m
yf= 0m
xi=0m


The Attempt at a Solution


i am trying to figure out what t equals based on the y-component equation
 
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By t do you mean how long it takes the projectile to hit the target? Is that what you're solving for?