Kinematics problem-finding total distance

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SUMMARY

The discussion focuses on a kinematics problem involving a particle moving at 5 m/s that reverses direction after 1 second, maintaining a constant acceleration. The key equation used is d = 1/2 (v0 + v)t, which calculates displacement rather than total distance. Participants clarify that total distance, a scalar quantity, should be calculated as the integral of the absolute velocity over time, leading to the conclusion that the total distance traveled is 5 m.

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  • Understanding of kinematics principles
  • Familiarity with the concepts of displacement and distance
  • Knowledge of the equation d = 1/2 (v0 + v)t
  • Basic calculus for integrating velocity
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Violagirl
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Homework Statement


A particle moving at 5 m/s reverses its direction in 1 s to move at 5 m/s in the opposite direction. If its acceleration is constant, what distance does it travel?

A) 1.25 m

B) 2.5 m

C) 5 m

D) 10 m



Homework Equations


d = 1/2 (v0 + v)t


The Attempt at a Solution



Since we need to find d:
d = 1/2 (5 + (-5+)(1)

d = 0

This clearly was off...I was going to see if someone would be able to help me understand this problem better.
 
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You're right. May be they want the total distance traveled instead of the displacement that you correctly calculated.
 
dauto said:
May be they want the total distance traveled instead of the displacement that you correctly calculated.
Yes, distance is a scalar, so generally it means ##\int|\vec v|.dt##. Displacement is a vector, ##\int\vec v.dt##
 

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