Kinemetics Question - theoretical subsitution

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SUMMARY

The discussion centers on a kinematics problem involving the equation s=ut + (1/2)at². The user questions the validity of squaring the time difference (t2-t1) before substituting it into the equation, arguing that it leads to an incorrect larger value for acceleration. The correct approach involves recognizing that the initial velocity (u1) at time t1 is not zero, leading to the formulation h = (a t1)(t2-t1) + (1/2)a(t2-t1)². Ultimately, the user confirms that the teacher's answer is indeed correct upon proper evaluation of the equation.

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Homework Statement



This is for personal study and as I am on study leave its a bit hard to contact a teacher.

This is the question; (the circled answer was the teachers answer)

2sba5pl.jpg


I'm unsure as to why you would individually square the times before subtracting as the actual time is (t2-t1) substituted into time on the equation, squaring before will result in a larger value (small value for acceleration though). It is possible the teacher merely got it wrong (has been known to happen).

Homework Equations



s=ut + (1/2)at^2

The Attempt at a Solution



2dv7hpl.jpg
 
Last edited:
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Your equation,  h = 0(t2-t1) + (1/2)a(t2-t1)2  is in error.

The velocity, u1, at time, t1 is not zero. This velocity is give by:
u1 = u0 + a(t1-t0) = 0 + a t1 = a t1 .​

∴ h = u1(t2-t1) + (1/2)a(t2-t1)2
= (a t1)(t2-t1) + (1/2)a(t2-t1)2

If you multiply this all out, combine like terms and then factor it, you will find that your teacher did indeed give the correct answer.

BTW: There is an easier way to come up with his answer. I thought it better to use what you started with.
 

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