MHB KRISTINE's question at Yahoo Answers (Set inclusion)

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To prove that A is a subset of C given that A is a subset of the union of B and C, and that the intersection of A and B is empty, one can use a contradiction approach. If an element x belongs to A, it must belong to either B or C. However, if x were in B, it would contradict the condition that A and B have no elements in common. Therefore, it must be true that x is in C, confirming that A is indeed a subset of C. This logical deduction effectively demonstrates the relationship between the sets.
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Hello KRISTINE,

By hypothesis, $(i)\;A\subset B\cup C\quad(ii)\;A\cap B=\emptyset$

If $x\in A$, then (by $(i)$) $x\in B$ or $x\in C$.

Suppose $x\in B$. Then, (by $(ii)$) $x\not \in A$ which contradicts the hypothesis $x\in A$. So, necessarily $x\in C$. We have proven $A\subset C$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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