MHB Laplace Transform Help: Solving for Unknown Variables in Electrical Circuits

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The discussion revolves around solving a differential equation using the Laplace transform, specifically for an electrical circuit with given parameters. The user successfully transforms the equation but struggles to find the inverse Laplace transform of the resulting expression. A suggestion is made to express the solution in a form that allows for easier inverse transformation by identifying constants α and ω. The correctness of the user's work up to the point of obtaining the expression for X is confirmed, despite some minor inconsistencies. The conversation emphasizes the importance of identifying the right constants for the inverse transform to proceed with the solution.
Sophie1
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Evening All

I have had a go at a laplace transform and got stuck.

$$\frac{d^2v}{dt^2}+\frac R L \d v t+\frac 1{LC}v=\frac 1{LC}V_0$$

$$R=12 \Omega, L=0.16H, C=10^{-4}F, V_0=6V, v(0)=0, v'(0)=0$$

so subbing these in i get
$$\mathscr L \left[ \frac {d^2v}{dt^2}+75\d v t+62500 v \right]=\mathscr L[375000]$$

$$S^2X-Sx(0)-x'(0)+75(SX-x(0))+62500v=\frac{375000}{S}$$

subbing $v(0)=0, x'(0)=0$

$$S^2X+75SX+62500X=\frac{375000}{S}$$

$$X(S^2+75S+62500)=\frac{375000}{S}$$

$$X= \frac{375000}{S(S^2+75S+62500)}$$

not I'm stuck as i can't an inverse form to change it back into.

can someone help?
 
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Sophie said:
Evening All

I have had a go at a laplace transform and got stuck.

$$\frac{d^2v}{dt^2}+\frac R L \d v t+\frac 1{LC}v=\frac 1{LC}V_0$$
$$R=12 \Omega, L=0.16H, C=10^{-4}F, V_0=6V, v(0)=0, v'(0)=0$$
(snip)
$$X= \frac{375000}{S(S^2+75S+62500)}$$

not I'm stuck as i can't an inverse form to change it back into.

Hi Sophie! Welcome to MHB! ;)

Suppose we could write $X$ as:
$$X = \frac A S + \frac {BS + C}{(s+\alpha)^2 + \omega^2}$$
for some yet to be determined $A,B,C,\alpha,\omega$.
Could you then find the inverse transform? (Wondering)
 
could you give me a pointer of where to begin. I have not used or even see α,ω. With respect to laplace transform.
 
Sophie said:
could you give me a pointer of where to begin. I have not used or even see α,ω. With respect to laplace transform.

From wiki:
$$\mathcal L^{-1}\left[\frac{s+\alpha}{(s+\alpha)^2+\omega^2}\right] = e^{-\alpha t} \cos(\omega t) \cdot u(t)$$

So if we can find such constants $\alpha,\omega$ we can find the inverse transform.
And we have that:
$$S^2+75S+62500 = (S+\alpha)^2 + \omega^2$$
so we just need to figure out what these $\alpha,\omega$ are... (Thinking)
 
Would you be able to confirm that my working out upto the point i asked is correct as I'm not finding the answer. I will carry on trying.
 
Sophie said:
Would you be able to confirm that my working out upto the point i asked is correct as I'm not finding the answer. I will carry on trying.

Your working up to:
$$X= \frac{375000}{S(S^2+75S+62500)}$$
is correct (disregarding some inconsistencies in $v$, $V$, and $x$ in the intermediate steps).
(Nod)
 

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