Laplace Transform Help: Solving for Unknown Variables in Electrical Circuits

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Discussion Overview

The discussion revolves around solving a differential equation related to electrical circuits using the Laplace transform. Participants are attempting to find the inverse Laplace transform of a derived expression for voltage, given specific parameters and initial conditions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a differential equation and the corresponding Laplace transform, leading to an expression for \(X\).
  • Another participant suggests expressing \(X\) in a different form to facilitate finding the inverse transform, introducing parameters \(\alpha\) and \(\omega\).
  • Some participants express uncertainty about the parameters \(\alpha\) and \(\omega\) and seek guidance on how to identify them.
  • There is a request for confirmation of the correctness of the calculations leading up to the expression for \(X\), with acknowledgment of some inconsistencies in variable notation.

Areas of Agreement / Disagreement

Participants generally agree on the correctness of the calculations up to a certain point, but there is uncertainty regarding the identification of parameters needed for the inverse transform. The discussion remains unresolved regarding the next steps to take.

Contextual Notes

There are noted inconsistencies in variable notation that may affect clarity. The identification of \(\alpha\) and \(\omega\) is not yet resolved, and there may be missing assumptions regarding the transformation process.

Sophie1
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Evening All

I have had a go at a laplace transform and got stuck.

$$\frac{d^2v}{dt^2}+\frac R L \d v t+\frac 1{LC}v=\frac 1{LC}V_0$$

$$R=12 \Omega, L=0.16H, C=10^{-4}F, V_0=6V, v(0)=0, v'(0)=0$$

so subbing these in i get
$$\mathscr L \left[ \frac {d^2v}{dt^2}+75\d v t+62500 v \right]=\mathscr L[375000]$$

$$S^2X-Sx(0)-x'(0)+75(SX-x(0))+62500v=\frac{375000}{S}$$

subbing $v(0)=0, x'(0)=0$

$$S^2X+75SX+62500X=\frac{375000}{S}$$

$$X(S^2+75S+62500)=\frac{375000}{S}$$

$$X= \frac{375000}{S(S^2+75S+62500)}$$

not I'm stuck as i can't an inverse form to change it back into.

can someone help?
 
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Sophie said:
Evening All

I have had a go at a laplace transform and got stuck.

$$\frac{d^2v}{dt^2}+\frac R L \d v t+\frac 1{LC}v=\frac 1{LC}V_0$$
$$R=12 \Omega, L=0.16H, C=10^{-4}F, V_0=6V, v(0)=0, v'(0)=0$$
(snip)
$$X= \frac{375000}{S(S^2+75S+62500)}$$

not I'm stuck as i can't an inverse form to change it back into.

Hi Sophie! Welcome to MHB! ;)

Suppose we could write $X$ as:
$$X = \frac A S + \frac {BS + C}{(s+\alpha)^2 + \omega^2}$$
for some yet to be determined $A,B,C,\alpha,\omega$.
Could you then find the inverse transform? (Wondering)
 
could you give me a pointer of where to begin. I have not used or even see α,ω. With respect to laplace transform.
 
Sophie said:
could you give me a pointer of where to begin. I have not used or even see α,ω. With respect to laplace transform.

From wiki:
$$\mathcal L^{-1}\left[\frac{s+\alpha}{(s+\alpha)^2+\omega^2}\right] = e^{-\alpha t} \cos(\omega t) \cdot u(t)$$

So if we can find such constants $\alpha,\omega$ we can find the inverse transform.
And we have that:
$$S^2+75S+62500 = (S+\alpha)^2 + \omega^2$$
so we just need to figure out what these $\alpha,\omega$ are... (Thinking)
 
Would you be able to confirm that my working out upto the point i asked is correct as I'm not finding the answer. I will carry on trying.
 
Sophie said:
Would you be able to confirm that my working out upto the point i asked is correct as I'm not finding the answer. I will carry on trying.

Your working up to:
$$X= \frac{375000}{S(S^2+75S+62500)}$$
is correct (disregarding some inconsistencies in $v$, $V$, and $x$ in the intermediate steps).
(Nod)
 

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