Laplace Transform Help: Solving for Unknown Variables in Electrical Circuits

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SUMMARY

The discussion focuses on solving a second-order differential equation using the Laplace Transform in the context of electrical circuits. The equation provided is $$\frac{d^2v}{dt^2}+\frac{R}{L}\frac{dv}{dt}+\frac{1}{LC}v=\frac{1}{LC}V_0$$ with specific values for resistance (R = 12 Ω), inductance (L = 0.16 H), capacitance (C = 10-4 F), and input voltage (V0 = 6 V). The user successfully derives the Laplace Transform but struggles to find the inverse transform. A suggestion is made to express the solution in a form that allows for easier inversion by identifying constants α and ω.

PREREQUISITES
  • Understanding of Laplace Transforms and their properties
  • Familiarity with differential equations, particularly second-order equations
  • Knowledge of electrical circuit theory, including concepts of resistance, inductance, and capacitance
  • Ability to perform algebraic manipulations and partial fraction decomposition
NEXT STEPS
  • Learn how to perform partial fraction decomposition for Laplace Transforms
  • Study the inverse Laplace Transform techniques, focusing on standard forms
  • Explore the relationship between the coefficients in the characteristic equation and the constants α and ω
  • Review examples of solving second-order differential equations in electrical circuits using Laplace Transforms
USEFUL FOR

Electrical engineers, students studying circuit analysis, and anyone interested in applying Laplace Transforms to solve differential equations in electrical systems.

Sophie1
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Evening All

I have had a go at a laplace transform and got stuck.

$$\frac{d^2v}{dt^2}+\frac R L \d v t+\frac 1{LC}v=\frac 1{LC}V_0$$

$$R=12 \Omega, L=0.16H, C=10^{-4}F, V_0=6V, v(0)=0, v'(0)=0$$

so subbing these in i get
$$\mathscr L \left[ \frac {d^2v}{dt^2}+75\d v t+62500 v \right]=\mathscr L[375000]$$

$$S^2X-Sx(0)-x'(0)+75(SX-x(0))+62500v=\frac{375000}{S}$$

subbing $v(0)=0, x'(0)=0$

$$S^2X+75SX+62500X=\frac{375000}{S}$$

$$X(S^2+75S+62500)=\frac{375000}{S}$$

$$X= \frac{375000}{S(S^2+75S+62500)}$$

not I'm stuck as i can't an inverse form to change it back into.

can someone help?
 
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Sophie said:
Evening All

I have had a go at a laplace transform and got stuck.

$$\frac{d^2v}{dt^2}+\frac R L \d v t+\frac 1{LC}v=\frac 1{LC}V_0$$
$$R=12 \Omega, L=0.16H, C=10^{-4}F, V_0=6V, v(0)=0, v'(0)=0$$
(snip)
$$X= \frac{375000}{S(S^2+75S+62500)}$$

not I'm stuck as i can't an inverse form to change it back into.

Hi Sophie! Welcome to MHB! ;)

Suppose we could write $X$ as:
$$X = \frac A S + \frac {BS + C}{(s+\alpha)^2 + \omega^2}$$
for some yet to be determined $A,B,C,\alpha,\omega$.
Could you then find the inverse transform? (Wondering)
 
could you give me a pointer of where to begin. I have not used or even see α,ω. With respect to laplace transform.
 
Sophie said:
could you give me a pointer of where to begin. I have not used or even see α,ω. With respect to laplace transform.

From wiki:
$$\mathcal L^{-1}\left[\frac{s+\alpha}{(s+\alpha)^2+\omega^2}\right] = e^{-\alpha t} \cos(\omega t) \cdot u(t)$$

So if we can find such constants $\alpha,\omega$ we can find the inverse transform.
And we have that:
$$S^2+75S+62500 = (S+\alpha)^2 + \omega^2$$
so we just need to figure out what these $\alpha,\omega$ are... (Thinking)
 
Would you be able to confirm that my working out upto the point i asked is correct as I'm not finding the answer. I will carry on trying.
 
Sophie said:
Would you be able to confirm that my working out upto the point i asked is correct as I'm not finding the answer. I will carry on trying.

Your working up to:
$$X= \frac{375000}{S(S^2+75S+62500)}$$
is correct (disregarding some inconsistencies in $v$, $V$, and $x$ in the intermediate steps).
(Nod)
 

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