Liapunov function (扁頭科學's question at Yahoo Answers)

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The discussion focuses on constructing a Liapunov function of the form ax² + cy² to demonstrate the asymptotic stability of the critical point at the origin for the system defined by the differential equations dx/dt = -x³ + xy² and dy/dt = -2x²y - y³. By setting a = c = 1, the resulting Liapunov function L_v(f)(x,y) yields a negative value for all points (x,y) ≠ (0,0), confirming that the origin is asymptotically stable. This establishes that the chosen Liapunov function is a Strict Lyapunov Function at the origin.

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Fernando Revilla
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Here is the question:

Construct a suitable Liapunov function of the form ax^2+cy^2,
where a and c are to be determined. Then show that the critical
point at the origin is of the indicated type.
1. dx/dt = -x^3+xy^2, dy/dt = -2x^2y-y^3; asymptotically stable

Here is a link to the question:

Differential equation (Liapunov function)? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Hello 扁頭科學,

If $f(x,y)=ax^2+cy^2$, then: $$L_v(f)(x,y)=\nabla f(x,y)\cdot (v_1,v_2)=(2ax,2cy)\cdot (-x^3+xy^2,-2x^2y-y^3)=\\-2ax^4+2ax^2y^2-4cx^2y^2-2cy^4$$ If $a=c=1$, we get $L_v(f)(x,y)=-2(x^4+x^2y^2+y^4)<0$ for all $(x,y)\ne (0,0)$. This means that $f$ is a Strict Lyapunov Function at $(0,0).$ As a consequence, $(0,0)$ is asymptotically stable.
 

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