Likelihood of inheriting autosomal dominant diseases

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SUMMARY

The inheritance of Huntington's disease follows a specific genetic pattern based on the genotype of the affected parent. If a parent is heterozygous dominant (Hh), there is a 50% chance of passing the disease allele to offspring. Conversely, if the parent is homozygous dominant (HH), the chance of offspring inheriting the disease is 100%. The discussion highlights that the actual probability of inheriting the disease may be more complex, factoring in the rarity of homozygous dominant individuals in the population, leading to an estimated probability of 75% when considering the prevalence of heterozygotes.

PREREQUISITES
  • Understanding of basic genetics, including dominant and recessive alleles
  • Familiarity with Punnett squares for predicting genetic inheritance
  • Knowledge of Huntington's disease and its genetic implications
  • Awareness of population genetics and allele frequency concepts
NEXT STEPS
  • Research the genetic mechanisms of Huntington's disease inheritance
  • Study Punnett square applications in various genetic scenarios
  • Examine population genetics to understand allele frequency and its impact on disease prevalence
  • Explore the implications of heterozygosity and homozygosity in genetic disorders
USEFUL FOR

Geneticists, medical professionals, students studying genetics, and individuals interested in understanding the inheritance patterns of autosomal dominant diseases.

Qube
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If one of your parents has Huntington's disease, you have a 50% chance of getting the gene for the disease.

This IS wrong. This only holds true if one of your parents is HETEROZYGOUS dominant.

Hh x hh => 50% chance of offspring having Huntington's disease.

However, if one of your parents is HOMOZYGOUS DOMINANT ..

HH x hh => 100% chance of offspring having Huntington's diseases.

Simple Punnett squares will verify the above.

Therefore, the probability should be 75% if one parent has Huntington's disease. Am I right?
 
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Qube said:
This IS wrong. This only holds true if one of your parents is HETEROZYGOUS dominant.

Hh x hh => 50% chance of offspring having Huntington's disease.

However, if one of your parents is HOMOZYGOUS DOMINANT ..

HH x hh => 100% chance of offspring having Huntington's diseases.

Simple Punnett squares will verify the above.

Therefore, the probability should be 75% if one parent has Huntington's disease. Am I right?

I don't know what you are quoting or context, but I'd guess this is an approximation based on homozygous being rare in the population.

The dynamics of Huntingdon's is a bit more complex than just the inheritance of a stable chromosome, and was explained in a recent thread on PF.
 
You are making the faulty assumption that heterozygotes and homozygotes are equally abundant. In reality, the probability is 0.5p+(1-p), where p is the proportion of Huntington's patients who are heterozygous for the disease allele. As mentioned by epenguin, the disease allele is rare, so there are many more heterozygotes than homozygotes, and p~1.
 

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