Limit Inferior and Limit Superior of a Sequence with Alternating Terms

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SUMMARY

The limit inferior (liminf) and limit superior (limsup) of the sequence defined by xn = n(1-(-1)^n) are determined as follows: liminf(xn) equals 0, while limsup(xn) does not exist. The limsup is calculated using the definition \limsup_{n\rightarrow \infty}=\lim_{n\rightarrow \infty}(\sup_{m\geq n}x_m), which indicates that the peaks of the sequence increase indefinitely when n is odd. Consequently, the last peak approaches infinity, confirming that limsup does not exist.

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  • Understanding of sequences and their limits
  • Familiarity with the concepts of limit inferior and limit superior
  • Knowledge of mathematical notation for limits
  • Basic algebraic manipulation skills
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  • Study the formal definitions of limit inferior and limit superior in advanced calculus
  • Explore examples of sequences with known liminf and limsup values
  • Learn about convergence and divergence of sequences
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muso07
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Homework Statement


Find liminf(xn) and limsup(xn) for xn = n(1-(-1)^n)

Homework Equations


The Attempt at a Solution


I'm not really getting liminf and limsup, but stumbled through the method in my textbook and got liminf=0, limsup doesn't exist.

Is that right? I don't think I did it right. If it's wrong, I can type out my working (I'd just prefer not to since it's pretty late).
 
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You are correct. I fins the easiest definition of limsup to be:

\limsup_{n\rightarrow \infty}=\lim_{n\rightarrow \infty}(\sup_{m\geq n}x_m)

That is: as n approaches infinity, look at all the "peaks" of the x_m for m\geq n. You are looking for the "last peak".

In the case of this function, the peaks get larger and larger (they occur when n is odd), so the "last one" is infinity, ie. it doesn't exist.

Similarly for liminf, the "troughs" of the function are all zero (when n is even), so the "last one" will also be zero.

I don't know if this will help much...I remember also being very confused by liminf and limsup when I first came across them!
 
It helped a lot, thanks!
 

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