Linear Algebra Problem: Solving for T in F(R) with Given Functions

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Let F be the vector space of all functions mapping [tex]R[/tex] into [tex]R[/tex], and let [tex]T:F\rightarrow F[/tex] be a linear transformation such that [tex]T(e^{2x})=x^{2}[/tex], [tex]T(e^{3x})=sinx[/tex], and [tex]T(1)=cos5x[/tex]. Find the following, if it is determined by this data.

[tex]T(e^{5x})[/tex]
[tex]T(3e^{4x})[/tex]
[tex]T(3+5e^{3x})[/tex]
[tex]T(\frac{e^{4x}+2e^{5x}}{e^{2x}})[/tex]
 
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I have no idea what to do here. Does this involve the kernel of T?
 
Nothing000 said:
I have no idea what to do here. Does this involve the kernel of T?

Try using the properties of a linear transformation: http://mathworld.wolfram.com/LinearTransformation.html" .
 
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So am I supposed to factor out the [tex]e^{x}[/tex] term like this

[tex]T(e^{3x})=sinx[/tex]
[tex]e^{x}T(e^{2x})=sinx[/tex]
[tex]T(e^{2x})=\frac{sinx}{e^{x}}[/tex]

and since [tex]T(e^{2x})=x^{2}[/tex]

it must be true that [tex]\frac{sinx}{e^{x}}=x^{2}[/tex]

Am I on the right track?
 
Oh wait, that can't be right, because [tex]e^{x}[/tex]
is not a constant. Duh. :rolleyes:
 
So the only one that I actually can figure out is
[tex]T(3+5e^{3x})[/tex]
since it is preserved by scaler multiplication and vector addition. Right?

[tex]T(3+5e^{3x})=T(3)+T(5e^{3x})[/tex]

[tex]\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =3T(1)+5T(e^{3x})[/tex]

[tex]\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =3cos5x+5sinx[/tex]

Is that right?
 
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Yes, looks okay. Hint regarding the last one: [tex]T(\frac{e^{4x}+2e^{5x}}{e^{2x}}) = T(\frac{e^{4x}}{e^{2x}}+\frac{2e^{5x}}{e^{2x}})[/tex].
 
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[tex]T(\frac{e^{4x}+2e^{5x}}{e^{2x}}) = T(\frac{e^{4x}}{e^{2x}}+\frac{2e^{5x}}{e^{2x}})[/tex]
Is this what you mean?
 
Thank you so much bro. I REALLY apreciate the assistance. I owe you one. Gotto go to my L.A. class now. THanks.