Linear Transformation: Solving Coefficient Matrix and Evaluating T(e1) and T(e2)

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 1K views
Clandry
Messages
74
Reaction score
0
I attached the problem. I'm not sure if I'm misinterpreting the question, but this problem seems really easy, which is usually not the case with my class.

for part a) isn't that just the coefficient matrix of the right hand side?
This makes A:
1 -2
3 1
0 2



for part b) T(e1)=T[1 0]^t=[1 3 0]^t
T(e2)=T[0 1]^t=(-2 1 2)^t
Is this right?
 

Attachments

  • Untitled.png
    Untitled.png
    6.2 KB · Views: 459
Physics news on Phys.org
Clandry said:
I attached the problem. I'm not sure if I'm misinterpreting the question, but this problem seems really easy, which is usually not the case with my class.

for part a) isn't that just the coefficient matrix of the right hand side?
This makes A:
1 -2
3 1
0 2



for part b) T(e1)=T[1 0]^t=[1 3 0]^t
T(e2)=T[0 1]^t=(-2 1 2)^t
Is this right?

Looks good to me.