Log2 of 41/2 = 1: Simplifying Logarithms in Simple Steps

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Homework Help Overview

The discussion revolves around the simplification of logarithmic expressions, specifically focusing on the relationship between logarithms and exponents. Participants are examining the equation involving logarithms with bases 2 and 4.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to express a mathematical statement in logarithmic form but questions its validity. Some participants explore the equivalence of logarithmic expressions and the implications of different bases.

Discussion Status

The discussion includes participants clarifying their understanding of logarithmic identities and exploring the relationships between different bases. There is acknowledgment of confusion regarding the original statement and references to textbook examples that illustrate similar concepts.

Contextual Notes

Participants reference a textbook that presents a specific logarithmic identity, which adds to the complexity of the discussion. There is an implicit assumption that the participants are familiar with logarithmic properties and their applications.

lionely
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Write in log form

2= 41/2I wrote this log2 41/2 = 1?

But looking at what I wrote doesn't make sense...
 
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Why it doesn't make sense to you? :confused:
 
oh wow I'm sorry I just noticed it...
2^1= does equal 4^1/2 = 2 ... I was confused because in the back of the book I saw log4 2= 1/2
 
lionely said:
oh wow I'm sorry I just noticed it...
2^1= does equal 4^1/2 = 2 ... I was confused because in the back of the book I saw log4 2= 1/2
Yes that's also true. loga(x)= y is equivalent to ay= x. Taking the logarithm, base 4, of both sides of 2= 41/2 gives log4(2)= log4(41/2)= 1/2. But taking the logarithm, base 2, gives log2(2)= 1= log2(41/2)= log2((22)1/2)= log2(21)= 1.
 

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